Saved Bookmarks
| 1. |
A ladder 25m long reaches a window of a building 20m above the ground. Find the distancebetween foot of the ladder and the building. |
|
Answer» Applying Pythagoras theorem...AC^2=AB^2+BC^225^2-20^2=BC^2sqrt(625-400)=BCsqrt(225)=BC15 m=BC-is the distance |
|