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A ladder 25 m long reaches a window of a building 20 m above the ground. Determine the distance of the foot of ladder from the building |
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Answer» AC = length of LADDER = 25m BC = distance between building and tail of ladder = ? By Pythagoras THEOREM, AC^2 = AB^2 + BC^2 25^2 = 20^2 + BC^2 BC^2 = 625 - 400 = 225 BC = √225 BC = 15m Therefore, distance between tail of ladder and bottom of building is 15m |
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