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A jar contains a mixture of 175 ml water and 700 ml alcohol. Gopal takes out 10% of the mixture and substitutes it by water of the same amount. The process is repeated once again. The percentage of water in the mixture is now |
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Answer» uantity of alcohol in the mixture = 700700+175∗(90100)2∗[700+175] = 567 mlTherefore, FINAL quantity of water in the mixture = 875 - 567 = 308 mlHence, we can SAY that the PERCENTAGE of water in the mixture = 308875×100 = 35.2 % |
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