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A is twice as old as B . Five years ago A was 3 times as old as B . Find their present ages. |
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Answer» Answer: Let AGE of B is x Then age of A is 2x 5 years ago A is 3 times as OLD as B. 5 years ago the age of A was (2x-5) Similarly 5 years ago age of B was( x-5) According to the question, 2x-5=3(x-5) 2x-5=3x-15 x=10 yrs So, present age of B is x i. e 10 yrs and present age of A is 2x=2×10=20 yrs Step-by-step explanation: HOPE IT HELPSPLEASE MARK AS BRAINLIESTPLEASE FOLLOW ME DEAR FRIENDPLEASEHAVE A GREAT DAY DEAR10 THANKS + FOLLOW = INBOX |
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