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A is twice as efficient as B is and both of them together complete a piece of work in 27 days. find the time taken by B alone to complete half the same work.1. 81 days2. \(40\frac12\space days\)3. 41 days4. \(41\frac12\space days\) |
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Answer» Correct Answer - Option 2 : \(40\frac12\space days\) GIVEN: A's efficiency = 2 × B's efficiency Time taken to complete the work together = 27 days FORMULA USED: Work done = efficiency × time CALCULATION: The ratio of efficiency (A : B) = 2 : 1 Total efficiency = 3 Total work = 3 × 27 = 81 Time taken by B to complete the work = \(\frac{81}{1}= 81 days \) Time taken by B to complete half the work =\(\frac{81}{2}=40\frac12days\) |
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