A is 25% more efficient than B, and B takes 6 days more than A to comp

1.	A is 25% more efficient than B, and B takes 6 days more than A to complete a piece of work. How many days will B take to complete the same work?1. 30 days2. 20 days3. 24 days4. 28 days
Answer» Correct Answer - Option 1 : 30 days Given: A is 25% more efficient than A, B takes 6 days more than A to complete a piece of work. Concept: Efficiency is inversely proportional to the time. Calculation: Ratio of efficiency of A and B = 125 ∶ 100 Ratio of time taken by A and B = 100 ∶ 125 Let A takes 100x days, and B takes 125x days to complete a piece of work. Days taken by B – Days taken by A = 6 ⇒ 125x – 100x = 6 ⇒ 25x = 6 ⇒ x = 6/25 Days taken by A = 100x ⇒ 100 × 6/25 ⇒ 4 × 6 ⇒ 24 And, days taken by B = 125x ⇒ 125 × 6/25 ⇒ 5 × 6 ⇒ 30 ∴ B will take 30 days to complete the same work.

A is 25% more efficient than B, and B takes 6 days more than A to complete a piece of work. How many days will B take to complete the same work?1. 30 days2. 20 days3. 24 days4. 28 days

Answer» Correct Answer - Option 1 : 30 days

Given:

A is 25% more efficient than A, B takes 6 days more than A to complete a piece of work.

Concept:

Efficiency is inversely proportional to the time.

Calculation:

Ratio of efficiency of A and B = 125 ∶ 100

Ratio of time taken by A and B = 100 ∶ 125

Let A takes 100x days, and B takes 125x days to complete a piece of work.

Days taken by B – Days taken by A = 6

⇒ 125x – 100x = 6

⇒ 25x = 6

⇒ x = 6/25

Days taken by A = 100x

⇒ 100 × 6/25

⇒ 4 × 6

⇒ 24

And, days taken by B = 125x

⇒ 125 × 6/25

⇒ 5 × 6

⇒ 30

∴ B will take 30 days to complete the same work.

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