(A): In the following circuit, emf is 2V and internal resistance of the cell is 1Omega and R=1Omega then reading of the voltmeter is 1V. (R ) : V = E-IR where E = 2V, I = 2//2 = 1A

(A): In the following circuit, emf is 2V and internal resistance of th

1.	(A): In the following circuit, emf is 2V and internal resistance of the cell is 1Omega and R=1Omega then reading of the voltmeter is 1V. (R ) : V = E-IR where E = 2V, I = 2//2 = 1A
Answer» Both 'A' and 'R' are true and 'R' is the correct EXPLANATION of 'A' Both 'A' and 'R' are true and 'R' is not the correct explanation of 'A' 'A' is true and 'R' is FALSE 'A' is false and 'R' is false Answer :B

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(A): In the following circuit, emf is 2V and internal resistance of the cell is 1Omega and R=1Omega then reading of the voltmeter is 1V. (R ) : V = E-IR where E = 2V, I = 2//2 = 1A

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