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a If one zero of a polynomial 322-8x + 2k+ 1 is seven times the other, find the value of k |
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Answer» 3x²-8x+2k+1 a=3, b=-8 ,c=2k+1suppose the zeroes of the equation are α and β . by the given condition α=7βas we know , α+β=-b/a7β+β=-(-8)/38β=8/3β=8/3×1/8=1/3αβ=c/a7β×β=2k+1/37×1/3×1/3=2k+1/37/9=2k+1/321/9=2k+121/9-1=2k12/9=2k4/3=2k4/6=k2/3=k |
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