A ietal parallelopiped of measures 16 cm x 1lem x 10 cm was melted tom

1.	A ietal parallelopiped of measures 16 cm x 1lem x 10 cm was melted tomoke coins. How many coins were mode if the thickness and diameter of eachcoin was 2 mm and 2 cm respectively ?s4 cm resnectively. To level the
Answer» Given : A metal parallelepiped of measures 16 cm ×11 cm ×10cm was melted to make coins. To Find : How many coins were made if the thickness and diameter of each coin was 2mm and 2 cm respectively Solution : Volume of metal piped = 16 cm ×11 cm ×10cm =1760 cubic cm Now Thicknes of coin = 2mm 1 mm = 0.1 cm 2 mm = 0.2 cm Thus the thickness(h) of coin is 0.2 cm Radius of coin(r) = diameter /2 =2/2 =1 cm Since coin is in cylindrical shape . So, volume of coin = πr²h use π =3.14 = 3.141²0.2 =0.628 cubic cm Thus no. of coins were made = volume of pipe/volume of 1 coin =1760/0.628 =2802.54 Thus no. of coins were made is 2802 like my answer if you find it useful!

A ietal parallelopiped of measures 16 cm x 1lem x 10 cm was melted tomoke coins. How many coins were mode if the thickness and diameter of eachcoin was 2 mm and 2 cm respectively ?s4 cm resnectively. To level the

Answer»

Given : A metal parallelepiped of measures 16 cm ×11 cm ×10cm was melted to make coins.

To Find : How many coins were made if the thickness and diameter of each coin was 2mm and 2 cm respectively

Solution :

Volume of metal piped = 16 cm ×11 cm ×10cm =1760 cubic cm

Now Thicknes of coin = 2mm

1 mm = 0.1 cm

2 mm = 0.2 cm

Thus the thickness(h) of coin is 0.2 cm

Radius of coin(r) = diameter /2 =2/2 =1 cm

Since coin is in cylindrical shape .

So, volume of coin = πr²h

use π =3.14

= 3.14*1²*0.2

=0.628 cubic cm

Thus no. of coins were made = volume of pipe/volume of 1 coin

=1760/0.628 =2802.54

Thus no. of coins were made is 2802

like my answer if you find it useful!