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a) I310. The last digit of the number (373)333 isb) 2c) 3al 1 |
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Answer» 373¹=373373²=139129373³=51895117373⁴=19...............1373⁵=722................093 Hence the cyclicity of 373 is 4.So, when 333 is divided by 4 the remainder is 1, so 373 raised to the power 1 is 373, hence the last digit of the result is 373 raise to the power that is 3. Hence option c is correct. |
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