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A hydrogen atom in its ground state is irradiated by light of wavelength 970 Å. Taking hc / e = 1.237 x 10-6 eV m and the ground state energy of hydrogen atom as -13.6 eV, the number of lines present in the emission spectrum is |
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Answer» Unit of he/e in original paper is incorrect Energy available E = hc/λ = 1.237 x 10-6 evm / 970 x 10-10 m = 12 . 75 eV (4th energy level of hydrogen atom) Hence, the number of lines present in the emission spectrum = \(^4C_2 =6\) |
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