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A hydrogen atom emits a photon of energy 12.1 eV. Its orbital angular momentum changes by triangleL. Then triangleL equals :

Answer»

`1.05 XX 10^(-34)JS`
`2.11 xx 10^(-34)Js`
`3.16 xx 10^(-34)Js`
`4.22 xx 10^(-34)Js`

Solution :`E=-13.6ev, E_(2)=-3.4ev, E_(4)=-0.85ev`
`RARR E_(3)-E_(1)=12.1ev ("transition for n=3 to n=1")`
`triangle L=(3-1) (LAMBDA)/(2PI) =(lambda)/(pi) =2.11 xx 10^(-34)J_(s)`


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