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A hydrocarbon with the minimum number of carbon atoms, capable of showing both geometrical and optical isomerism is (a) 3-methylpentene (b) 3-methylpent-2-ene (c) 4-methylhex-2-ene (d) 4-methylhept-3-ene |
| Answer» A hydrocarbon with the minimum number of carbon atoms, capable of showing both geometrical and optical isomerism is (a) 3-methylpentene (b) 3-methylpent-2-ene (c) 4-methylhex-2-ene (d) 4-methylhept-3-ene | |