A hydrocarbon contain 80 percent of carbon.tge vapour density of compo

1.	A hydrocarbon contain 80 percent of carbon.tge vapour density of compound is 30 molecular formula of compound is
Answer» A hydrocarbon contains 80% of carbon. means, mass percentage of C = 80% then mass percentage of H = 20% . find percentage atomic mass ratio, for C ⇒80/12 = 20/3 for H ⇒20/1 = 20 find simple ratio of GIVEN NUMERICAL value. C : H = 20/3 : 20 = 1 : 3 so, empirical FORMULA of hydrogen is $CH_3$ as it is given, vapor density of hydrogen is 30. so, molar mass of hydrogen = 2 × vapor density = 2 × 30 = 60 g/mol. now, molecular mass = n × mass of empirical formula 60 = n (12 × 1 + 1 × 3) n = 4 hence, molecular formula of hydrocarbon is $C_4H_{12}$

A hydrocarbon contain 80 percent of carbon.tge vapour density of compound is 30 molecular formula of compound is

Answer»

A hydrocarbon contains 80% of carbon.

means, mass percentage of C = 80%

then mass percentage of H = 20% .

find percentage atomic mass ratio,

for C ⇒80/12 = 20/3

for H ⇒20/1 = 20

find simple ratio of GIVEN NUMERICAL value.

C : H = 20/3 : 20 = 1 : 3

so, empirical FORMULA of hydrogen is $CH_3$

as it is given, vapor density of hydrogen is 30.

so, molar mass of hydrogen = 2 × vapor density

= 2 × 30 = 60 g/mol.

now, molecular mass = n × mass of empirical formula

60 = n (12 × 1 + 1 × 3)

n = 4

hence, molecular formula of hydrocarbon is $C_4H_{12}$