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A hydraulic press consists of two cylinders of cross-sectional area 0.2m2 and 5.0m2 . The piston in the smaller area is pushed down with a force of 100N through a distance of 0.2m. Calculate: i) the pressure transmitted by the fluid ii) the pressure exerted by the piston in the large cylinder iii) the distance moved by the piston in the larger cylinder. |
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Answer» - PASCAL'S LAW CONCEPT :- The fluid PRESSURE is transmitted equally in all direction.SOLUTIONSWe have,pressure at smaller PISTON = F/A = 100/0.2 = 500 N/m²Thus, by pascal's law the pressure EXERTED by the fluid = the pressure exerted by the piston in the larger cylinder = 500 N/m³.Now,volume of liquid coming down in smaller piston side = volume of liquid going up in larger piston side.=> a1 × D1 = a2 × d2=> 0.2 × 0.2 = 5 × d2=> d2 = 0.008 m. Thus, required answer is (I) = 500 N/m²(ii) 500 N/m²(III) 0.008 m |
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