1.

A hydraulic lift at a service station can lift cars with a mass of 3500 kg. The area of cross section of the piston carrying the load is 500 cm'. What pressure does the smaller piston experience? g-9.8m/s)​

Answer»

Pressure=Force/Area= 500×10^4N/m² /3500×9.8=6.86×10⁵ N/m² HOPE it's HELPFUL to you ☺️plz MARK me BRAINLIST



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