Saved Bookmarks
| 1. |
A hydraulic lift at a service station can lift cars with a mass of 3500 kg. The area of cross section of the piston carrying the load is 500 cm'. What pressure does the smaller piston experience? g-9.8m/s) |
|
Answer» Pressure=Force/Area= 500×10^4N/m² /3500×9.8=6.86×10⁵ N/m² HOPE it's HELPFUL to you ☺️plz MARK me BRAINLIST |
|