A hunter has a machine gun that can fire 50 g bullets with a velocity

1.	A hunter has a machine gun that can fire 50 g bullets with a velocity of 150 ms-1. A 60 kg tiger springs at him with a velocity of 10 ms-1. How many bullets must the hunter fire into the targets so as to stop him in his track?
Answer» Given, m = mass of bullet = 50 gm = 0.050 kg M = mass of tiger = 60 kg v = velocity of bullet = 150 ms^-1 v = velocity of tiger = −10 ms^-1. (∵ It is coming from opposite direction) n = no. bullets fired per second at the tiger so as to stop it. p_i = 0, before firing …(i) p_f = n(mv) + MV …(ii) ∴ From the law of conservation of momentum, p_i = p_f or 0 = n(mv) + MV or n = \(-\frac{MV}{mv}\) = \(\frac{−60×(−10)}{0.05×150}\) = 80.

A hunter has a machine gun that can fire 50 g bullets with a velocity of 150 ms-1. A 60 kg tiger springs at him with a velocity of 10 ms-1. How many bullets must the hunter fire into the targets so as to stop him in his track?

Answer»

Given,

m = mass of bullet = 50 gm

= 0.050 kg

M = mass of tiger = 60 kg

v = velocity of bullet = 150 ms^-1

v = velocity of tiger

= −10 ms^-1.

(∵ It is coming from opposite direction)

n = no. bullets fired per second at the tiger so as to stop it.

p_i = 0, before firing …(i)

p_f = n(mv) + MV …(ii)

∴ From the law of conservation of momentum,

p_i = p_f

or 0 = n(mv) + MV

or n = \(-\frac{MV}{mv}\)

= \(\frac{−60×(−10)}{0.05×150}\)

= 80.