1.

a. How many excess electrons must be added to one plate and removed from the other to give a 5.000 nF parallel plate capacitor 25.0 J of stored energy ? b. How could you modify the geometry of this capacitor so that can store 50.0 J of energy without changing the charge on its plates?

Answer»

Solution :WITHOUT changing charge on the PLATES, we can make C half. `C=(epsi_(0)A)/(d)`, i.e. double the PLATE separation or inserting dielectric of dielectric of a VALUE such that C becomes.


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