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A household uses the following electrical appliances: i] Refrigerator of rating 400 W for 10 h each day. ii] Two electric fans of rating 80 W each for 6 h daily. iii] Six tube lights of 18 W each for 6 h daily. Calculate the energy consumed per day by each of these appliances in kWh. |
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Answer» Solution :i] Energy consumed per DAY by refrigerator = `0.4kWxx10h` `because` power of refrigerator = `400W=400/1000kW=0.4kW` = 4kWh ii] Energy consumed per day by fan = `2xx0.08kWxx6h` `because` power of each fan = `80W=80/1000kW=0.08kW` = 0.96kWh iii] Energy consumed per day by 6 tuve lights = `6xx0.018kWhxx6h` `because` power of each electric TUBE `=18W=18/1000kW=0.018kW` = 0.648 KWH |
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