A hot air balloon is rising vertically upwards at a constant velocity of 10 ms−1. When it is at a height of 45 m from the ground, a man bails out from it. After 3 s he opens his parachute and decelerates at a constant rate of 5 ms−2. After how long does the parachutist takes to hit the ground after his exit from the balloon?

A hot air balloon is rising vertically upwards at a constant velocity

1.	A hot air balloon is rising vertically upwards at a constant velocity of 10 ms−1. When it is at a height of 45 m from the ground, a man bails out from it. After 3 s he opens his parachute and decelerates at a constant rate of 5 ms−2. After how long does the parachutist takes to hit the ground after his exit from the balloon?
Answer» A hot air balloon is rising vertically upwards at a constant velocity of $10 {ms}^{- 1}$ . When it is at a height of $45 m$ from the ground, a man bails out from it. After $3 s$ he opens his parachute and decelerates at a constant rate of $5 {ms}^{- 2}$ . After how long does the parachutist takes to hit the ground after his exit from the balloon?

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