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A horizontal tube of uniform cross-sectional area `A` is bent in the form of `U` as shown in figure. If the liquid of density `rho` enters and leaves the tube with velcity v, then the extermal force `F` requried to hold the bend stationary is A. `F=0`B. `rhoAv^(2)`C. `2rhoAv^(2)`D. `(1)/(2) rhoAv^(2)` |
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Answer» Correct Answer - C `F=(Delta p)/(Delta t)=((Delta m)/(Delta t))(Delta v)` `=rho((Delta V)/(Delta t))(2v)` `=(rho)(Av)(2v)=2rhoAv^(2)`. |
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