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A horizontal force of 600 N pulls two masses 10 kg and 20 kg (lying on a frictionless table) connected by a light string. What is th tension in the string? Does the answer depend on which mass end the pull is applied? |
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Answer» Here, a = {600}/{10 + 20} = 20 ms-2 When force is applied on 10 kg mass, 600 - T = 10 x 200 ⇒ T = 400 N When force is applied on 20 kg mass, 600 - T = 20 x 20 ⇒ T = 200 N |
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