1.

A horizontal force of 15 N accelerates a 4 kg object from rest along a horizontal surface ata rate of 3 m s? At the end of 2 s. theobject's momentum will be(a) 12 kg m s -1 (b) 24 kg m s(c) 30 kg m s1 (d) 45 kg m s​

Answer»

f=ma15=4aa=15/4u=0, V=u+at v= 15/4×2v=7.5p=mvp = 4×7.5p = 30 KG m s-1



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