A horizontal force of 1200 gf is applied to a 1200 g block , which rest on a horizontal surface. If the coefficient of friction is 0•2, find the acceleration produced in the block .

A horizontal force of 1200 gf is applied to a 1200 g block , which res

1.	A horizontal force of 1200 gf is applied to a 1200 g block , which rest on a horizontal surface. If the coefficient of friction is 0•2, find the acceleration produced in the block .
Answer» Horizontal forceF=1.2kgwtF 1 =1.2×gNow frictional forceF=umgF=0.3×1.5×gF=0.45gLet ACCELERATION produced in the BODY be a.Now we haveF 1 −F=ma1.2g−0.45g=1.5a0.75g=1.5aa= 2g a=4.9m/s 2Explanation:PLEASE MARK me BRAINLIST

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A horizontal force of 1200 gf is applied to a 1200 g block , which rest on a horizontal surface. If the coefficient of friction is 0•2, find the acceleration produced in the block .​

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A horizontal force of 1200 gf is applied to a 1200 g block , which rest on a horizontal surface. If the coefficient of friction is 0•2, find the acceleration produced in the block .