1.

A horizontal compass is placed 0.800 cm due South from a straight vertical wire carrying a 6.00 A current in the direction shown in the figure above. The horizontal component of the earth's magnetic field at this location is Be = 4.50×10-5 T and points North.The angle between the compass needlepoint and the East is 163 degrees celsiusWhat is the magnitude of the B-field at the position of the compass?

Answer»

BCOS(73)=Be

B=Be/cos(73)=15.4×10^-5



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