1.

A hoop of mass M and radius R is hung from a support fixed in a wall . Its moment of inertia about the support is

Answer»

`2MR^2`
`3 M R^2`
`4 M R^2`
`6 M R^2`

Solution :A HOOP is a circular RING `therefore I_(0) = MR^(2)`
By theorem of PARALLEL axes ,
`I = I_(0) + MR^(2) = MR^(2) + MR^(2) = 2 MR^(2)`


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