1.

A hollow sphere of mass m and radius 'r' is rotating with velocity omega. It suddenly stops and 75% of K.E. is converted into heat. If its specific heat is 's' J/kg/K, the rise of temperature is :

Answer»

`(R^(2)omega^(2))/(4s)`
`(3R^(2)omega^(2))/(20s)`
`(R^(2)omega^(2))/(12s)`
`(2R^(2)omega^(2))/(3s)`

Solution :Here K.E. = Heat developed
`(75)/(100)XX(1)/(2)xx(2)/(3)MR^(2)omega^(2)=msthetaortheta=(R^(2)omega^(2))/(4s)`


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