1.

A hiker stands on the edge of a cliff 490 m above the ground and throws a stone horizontally with a speed of15ms−1.15ms−1. The time taken by the stone to reach the ground is

Answer»

Time taken by STONE to reach GROUND is

\sqrt{2h \div g}
time taken is SQUARE root of (2*490\10)
which is
7 \sqrt{2}
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