A hemispherical dome open at the base is made from a sheet of fibre. i

1.	A hemispherical dome open at the base is made from a sheet of fibre. if the radius of the hemispherical dome is 40cm and 13/170 of the fibre sheet actually used was wasted in making the dome, find the cost of the dome at the rate of rupees 3.5/- per 100cm square. (Take pie as 3.14) 1
Answer» Answer: ₹ 3808 Step-by-step EXPLANATION: Hii MATE :-) Here, r=40cm Wasted sheet= 13/170 of the total sheet SURFACE Are of dome= $2\pi \: {r}^{2}$ Now , $2 \times 3.14 \times 40 \times 40\\=2 \times 314 \times 4 \times 4\\ =314 \times 32\\=10048$ Surface Area of the Dome =10048cm² Now Let the area of fibre sheet =x According to Question, $10048 +( 13 \div 170) \times x = x\\=>10048 = x - (13 \div 170)x\\=>10048 = (157 \div 170)x\\=>x = 10880$ Now the Area of sheet required USED =10880cm² Cost of sheet used in MAKING of dome= $10880 \times 35 \div 100\\\\=1088 \times 3.5\\\\=\bold{3808}$ Cost of making the Dome = ₹ 3808 HOPE IT HELPS, PLEASE THANK, FOLLOW AND MARK AS BRAINLIEST.

A hemispherical dome open at the base is made from a sheet of fibre. if the radius of the hemispherical dome is 40cm and 13/170 of the fibre sheet actually used was wasted in making the dome, find the cost of the dome at the rate of rupees 3.5/- per 100cm square. (Take pie as 3.14) 1

Answer»

Answer:

Step-by-step EXPLANATION:

Hii MATE :-)

Here,

r=40cm

Wasted sheet= 13/170 of the total sheet

SURFACE Are of dome= $2\pi \: {r}^{2}$

Now ,

$2 \times 3.14 \times 40 \times 40\\=2 \times 314 \times 4 \times 4\\ =314 \times 32\\=10048$

Surface Area of the Dome =10048cm²

Now Let the area of fibre sheet =x

According to Question,

$10048 +( 13 \div 170) \times x = x\\=>10048 = x - (13 \div 170)x\\=>10048 = (157 \div 170)x\\=>x = 10880$

Now the Area of sheet required USED =10880cm²

Cost of sheet used in MAKING of dome=

$10880 \times 35 \div 100\\\\=1088 \times 3.5\\\\=\bold{3808}$

Cost of making the Dome = ₹ 3808

HOPE IT HELPS,

PLEASE THANK, FOLLOW AND MARK AS BRAINLIEST.