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A hemispherical bowl of radius R is set rotating about its axis of symmetry which is kept vertical A small block kept in the bowl rotates with the bowl without slipping on its surface If the surface of bowl is smooth and angle made by radius through the block with the vertical is 0 find the angular speed at which the bowl is rotating . |
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Answer» Solution :Here ` OA = R, ANGLEAOC = theta` Block moves in a horizontal circle with centre`C` and radius` r = AC = R sin theta` `:.` In equilibrium `N cos theta = MG` and `N sin theta = m OMEGA^(2) (R sin theta)` `N = m omega^(2) R` From(i)`m omega^(2) R cos theta = mg` ` omega = sqrt((g)/(R cos theta))` .
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