Saved Bookmarks
| 1. |
A hemispherical bowl is made of steel 0.25cm thick. The inner radius of the bowl is 5cm. Find the outer curved surface area of the bowl. |
|
Answer» It is given that Inner radius of the bowl = 5cm Thickness of the bowl = 0.25cm External radius = 5 + 0.25 = 5.25cm We know that Outer curved surface area of the bowl = 2 πr2 By substituting the values Outer curved surface area of the bowl = 2 × (22/7) × 5.252 On further calculation Outer curved surface area of the bowl = 2 × (22/7) × 27.5625 So we get Outer curved surface area of the bowl = 173.25 cm2 Therefore, the outer curved surface area of the bowl is 173.25 cm2. |
|