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A hemispherical bowl is made of steel 0.25 cm thick. The inside radius of the bowl is 5 cm. Find the volume of steel used in making the bowl. |
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Answer» Volume of a hemisphere = (2/3)πr3 Given, hemispherical bowl is made of steel 0.25 cm thick. The inside radius of the bowl is 5 cm. Outer radius = 5 + 0.25 cm = 5.25 cm Volume of steel used in the making of the bowl = \(\frac{2}{3}\times\)\(\frac{22}{7}\)\(\times\)(5.253 - 53) cm3 ⇒ Volume of steel used in the making of the bowl = 41.28 cm3 |
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