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A hemispherical bowl has a radius of 3.5 cm What would be the volume of water itwould contain? |
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Answer» Given,Radius of hemispherical bowl r = 3.5 cm Volume of hemispherical bowl= 2/3*pi*r^3= 2/3 * 22/7 * (3.5*3.5*3.5)= 22/3 * 3.5 * 3.5= 89.8 cm^3 Therefore,Volume of water it would contain = 89.8 cm^3 |
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