A hemisphere of lead of radius 7 cm is cast into a right circular cone

1.	A hemisphere of lead of radius 7 cm is cast into a right circular cone of height 49 cm. Find the radius of the base.
Answer» Volume of a sphere = \(\frac{2}{3}\)πr³ Volume of a cylinder = \(\frac{1}{3}\)πr²h Given, hemisphere of lead of radius 7 cm is cast into a right circular cone of height 49 cm ⇒ \(\frac{2}{3}\)π x 7³ = \(\frac{1}{3}\) x π x 49 x r² ⇒ r² = 14 ⇒ r = 3.74 cm

A hemisphere of lead of radius 7 cm is cast into a right circular cone of height 49 cm. Find the radius of the base.

Answer»

Volume of a sphere = \(\frac{2}{3}\)πr³

Volume of a cylinder = \(\frac{1}{3}\)πr²h

Given,

hemisphere of lead of radius 7 cm is cast into a right circular cone of height 49 cm

⇒ \(\frac{2}{3}\)π x 7³ = \(\frac{1}{3}\) x π x 49 x r²

⇒ r² = 14

⇒ r = 3.74 cm