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A heavy uniform plank of length L is supported by two force F, and F2 at points distant and from its ends as shown in the diagram. What is the ratio of F1 to Fz?plankEA) 2:5B) 3:5C) 5:8D) 2:3 |
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Answer» D) 2:3Explanation:This is a torque problem. To BALANCE the plank, the counter clockwise torque must be equal to the clockwise torque. To simplify this problem, let’s ASSUME the length of the plank is 8 meters. The left support is 1 meter from its left end.L/4 = 2 metersThe right support is 2 meters from the right end. Let the pivot point be at the center of the plank. F1 is 3 meters from this point. F2 is 2 meters from this point.Counter clockwise torque = F2 * 2Clockwise torque = F1 * 3F1 * 3 = F2 * 2F1/F2 = 2/3Thanks!I HOPE it HELPS you.Good LucK! |
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