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A heavy uniform chain lies on a horizontal top of table. If the coefficient of friction between the chain and thetable is 0.25, then the maximum percentage of thelength of the chain that can hang over one edge of thetable is(a) 20%(b) 25% (c) 35%(d) 15%​

Answer» LET x be the length of rope on table and (L−x) is the length hanging. Let total mass be M.  Therefore mass of hanged part & on table part are   L M  (L−x)&  L M   x respectivelyMaximum Friction force: F  MAX   =μN=μ(  L M   x)g=  L μMgx ​    Weight of hanging CHAIN: W=m  ′  g= L M (L−x)g= L M(L−xZFor system to be stable:       L M(L−x)g =  L μMgx   (L−x)=  4 1 ​ x  x=  5 4 ​   L Therefore hanging part is   5 L .(20%)Explanation:


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