1.

A heavy small sized sphere is suspended by a string of length 2. The sphere is rotated uniformly in a horizontal circle with the string making an angle theta with the vertical. The time period of this conical pendulum is

Answer»

`2 pisqrt((L tantheta)/( g))`
`2 PI sqrt((l COSTHETA)/(g))`
`2 pisqrt((1)/(g))`
`2 pi sqrt((l costheta)/(g))`

Solution :`2 pi sqrt((l costheta)/(g))`


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