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A heavy particle is projected with a velocity at an acure angle with the horizontal into a uniform gravitational field. The slope of the trajectory of the particle varies asA. B. C. D. |
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Answer» `y=x tan theta-(gx^(2))/(2u^(2)cos^(2)theta)` `rArr(dy)/(dx)=tan theta-((g)/(u^(2)cos^(2)theta))x` Putting x=`u costheta.t` `rArr(dy)/(dx)=tan theta-((g)/(u cos theta))t` `rArreq^(n)` of straght line with negative slope and +ve intercept. |
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