A heap of wheat is in the form of a cone whose diameter is 10.5 m and

1.	A heap of wheat is in the form of a cone whose diameter is 10.5 m and height is 3 m.its volume. The heap is to be covered by canvas to protect it from rain. Find thearea of the canvas required
Answer» Radius of the conical heap of wheat (r) = 10.5/2 m Height of the conical heap of wheat (h) = 3 m Volume of the conical heap of wheat = 1/3πr2h = 1/3 x 22/7 x (10.5/2)2x 3 = 173.25/2 = 86.625 m3 Slant height of the cone l = root under(√r2+ h2) = root under(√(10.5/2)2+ 32) =root under(√(5.25)2+ 32) =root under(√27.5625 + 9) =root uner(√36.5625) I = 6.05 m Area of canvas required = curved surface area of cone πrl= 22/7 x 10.5/2 x 6.05 = 99.825 m

A heap of wheat is in the form of a cone whose diameter is 10.5 m and height is 3 m.its volume. The heap is to be covered by canvas to protect it from rain. Find thearea of the canvas required

Answer»

Radius of the conical heap of wheat (r) = 10.5/2 m

Height of the conical heap of wheat (h) = 3 m

Volume of the conical heap of wheat = 1/3πr2h = 1/3 x 22/7 x (10.5/2)2x 3

= 173.25/2 = 86.625 m3

Slant height of the cone l = root under(√r2+ h2)

= root under(√(10.5/2)2+ 32) =root under(√(5.25)2+ 32)

=root under(√27.5625 + 9) =root uner(√36.5625)

I = 6.05 m

Area of canvas required = curved surface area of cone

πrl= 22/7 x 10.5/2 x 6.05 = 99.825 m