A harmonic osillator is represented by y=0.5cos (1500pi t+0.8) where 'y' and 't' are in 'm' and 's' respectively. Calculate (iv) period

A harmonic osillator is represented by y=0.5cos (1500pi t+0.8) where '

1.	A harmonic osillator is represented by y=0.5cos (1500pi t+0.8) where 'y' and 't' are in 'm' and 's' respectively. Calculate (iv) period
Answer» SOLUTION :Given, `y=0.5cos(1500pit+0.8)=0.5sin((PI)/(2)-1500pit-0.8)=0.5sin[-1500pit-(0.8-(pi)/(2))]` `y=-0.5sin[1500pit+(0.8-(pi)/(2))]` Now (iv) `"period "=(1)/("FREQUENCY")=(1)/(750)=0.00133=1.33xx10^(-3)s.`