1.

A harmonic osillator is represented by y=0.5cos (1500pi t+0.8) where 'y' and 't' are in 'm' and 's' respectively. Calculate (ii) frequency

Answer»

Solution :GIVEN, `y=0.5cos(1500pit+0.8)=0.5sin((pi)/(2)-1500pit-0.8)=0.5sin[-1500pit-(0.8-(pi)/(2))]`
`y=-0.5sin[1500pit+(0.8-(pi)/(2))]`
Now (ii) frequency `=(OMEGA)/(2K)=(1500pi)/(2PI)=750Hz.`


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