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A hammer of mass 1 kg moving with a speed of 6 ms-1 strikes a wall and comes to rest in 0.1 s. Find the1. Impulse2. Retarding force on the hammer3. Retardation |
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Answer» 1. The initial momantum of the hammer is, m × v = 1 kg × 6 ms-1 = 6 kg ms-1 = 6 Ns Impulse = F. t = Δ P = 0 – mv = – 6 Ns. 2. The force on the hammer F = Impulse/time = 6Ns/0.1s = 60 N. 3. Retardation = a = F/m = 60N/1kg = 60 ms-2. |
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