1.

A gun weighing 1000 kg recoils with a velocity of 3 × 10-2 m/s when a shell of mass 1 kg is shot from it. If the shell hits the target in 8 seconds, find the gun target distance.

Answer»

Initial momentum of the gun & that of shell is zero as they are at rest.

Recoil velocity of the gun v1 = – 3 × 10-2ms-1

Mass of the gun m1 = 1000kg

Mass of the shell m2 = 1 kg

velocity of the shell v2 =?

From the equation

m1 u1 + m2 u2 = m1v1 + m2 v2

0 = 1000(- 3 × 10-2 ) + 1 .v2

∴ v2 = 30ms-1

The gun target distance,

s = v2 × t

= 30 × 8

= 240m.



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