1.

a gun of mass 3 kg fires a bullet of mass 30gm. The bullet takes 0.003 sec to move through the barrel of the gun and acquires a velocity of 100m/s. Calculate - 1.the velocity with which the gun recoil. 2. the force exerted on the gun man due to recoil of gun.. PLZ solve it

Answer»

1. velocity with which gun RECOILS is 1m/s .
mass of gun * velocity of gun = mass of BULLET * velocity of bullet
3 * V = 30/1000 *100
3v = 0.03*100
3v = 3/100*100
3v=3
v=3/3
v=1



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