A golfer takes three putts to put the ball into the hole. The first sh

1.	A golfer takes three putts to put the ball into the hole. The first shot moves the ball 4m to the north, the second 2m to 45° to the southeast and the third 1m to 45° to the southwest, with which it achieves the goal. What displacement would have been needed to get the ball into the hole in the first stroke ?
Answer» ong>Answer: We choose +X east and +y north and measure all angles in the “standard” way (positive ones counterclockwise from +x, negative ones clockwise). Thus, VECTOR d1 has magnitude d1=3.66 (with the unit meter and three SIGNIFICANT figures assumed) and direction θ1=900 also. d2 has magnitude d2=1.83 and direction θ2=−450 and vector d3 has magnitude d3=0.91 and the direction θ3=−1350 we ADD the x and y COMPONENTS respectively. x:d1cosθ1+d2cosθ2+d3cosθ3=0.65m y:d1sinθ1+d2sinθ2+d3sinθ3=1.7m (a) The magnitude of the direct displacement (the vector sum d1+ Explanation: hope it help uh freind Mark me brainliest

A golfer takes three putts to put the ball into the hole. The first shot moves the ball 4m to the north, the second 2m to 45° to the southeast and the third 1m to 45° to the southwest, with which it achieves the goal. What displacement would have been needed to get the ball into the hole in the first stroke ?

Answer»

ong>Answer:

We choose +X east and +y north and measure all angles in the “standard” way (positive ones counterclockwise from +x, negative ones clockwise). Thus, VECTOR d1 has magnitude d1=3.66 (with the unit meter and three SIGNIFICANT figures assumed) and direction θ1=900 also. d2 has magnitude d2=1.83 and direction θ2=−450 and vector d3 has magnitude d3=0.91 and the direction θ3=−1350 we ADD the x and y COMPONENTS respectively.

x:d1cosθ1+d2cosθ2+d3cosθ3=0.65m

y:d1sinθ1+d2sinθ2+d3sinθ3=1.7m

(a) The magnitude of the direct displacement (the vector sum d1+

Explanation:

hope it help uh freind Mark me brainliest

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