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A golf player hits a golf ball of mass 100 g and imparts it a speed of 50 m/s. If golf stick remains in contact with the ball for `0.01` s, then the average force exerted by the golf stick on the ball.

Answer» Initially, ball was at rest, then ball gains a momentum `=(100)/(1000)xx50implies5N-s`
The momentum is gained in `0.01` s.
Hence, the average force `=(5)/(0.01)=500N`


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