Saved Bookmarks
| 1. |
A glass plate of length 3.5 cm and width 1.5 cm. what will be the maximum possible error in measuring the area of the plate?.Guys answer it fast I need help |
|
Answer» Relative ERROR in length = ΔL/L = 0.1/3.5 = 1/35 Relative error in width = ΔW/W = 0.1/1.5 = 1/15 Relative error in AREA ΔΑ/A = ΔL/L + ΔW/W = 1/35+1/15 = 2/21 Maximum POSSIBLE Error in area = ΔA/A × A = 2/21 × (1.5 × 3.5) = +0.5 or -0.5 cm^2 |
|