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A geostationary satellite is orbiting around earth at a height of 30,000Km in circular orbit. The radius of the earth is taken as 6,000 Km. The geostationary satellite comes back to its position in one revolution in exactly 24 hours. Let the acceleration due to gravity be 10m/s^2 and mass of satellite be 1000 Kg ; Calculate the work done in 12 hours when moving under gravitational force.1) 3.6 pi X 10^14 J 2)2 pi X 7.2 pi X 10^14J3)1.8 pi X 10^14 J 4)Zero J |
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Answer» A geostationary satellite is orbiting around earth at a height of 30,000Km in circular orbit. The radius of the earth is taken as 6,000 Km. The geostationary satellite comes back to its position in one revolution in exactly 24 hours. Let the acceleration due to gravity be 10m/s^2 and mass of satellite be 1000 Kg ; Calculate the work done in 12 hours when moving under gravitational force. 1) 3.6 pi X 10^14 J 2)2 pi X 7.2 pi X 10^14J 3)1.8 pi X 10^14 J 4)Zero J |
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