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A gaseous mixture of methane and ethylene in the ratio of a : b by volume occupies 30 ml. On complete combustion, the mixture yield 40 ml of `CO_(2)`. What volume of `CO_(2)` would have been obtained if the ratio would have been b : a?A. 30mlB. 40mlC. 50mlD. 60ml |
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Answer» Correct Answer - C `underset("a volume")(CH_(4))(g)+2O_(2)(g)rarrunderset("a volume")(CO_(2))(g)+2H_(2)O(l)` `underset("b volume")(C_(2)H_(4))(g)+3O_(2)(g)rarrunderset("2b volumne")(2CO_(2))(g)+2H_(2)O(l)` `30 = a+b" "b = 10, a = 20` `therefore40 = a +2b` If volume ratio becomes b : a `v_(CO_(2))=b+2a = 50 ml` |
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