A gaseous mixture contain equal mass of O2 and SO2 . the mole fraction

1.	A gaseous mixture contain equal mass of O2 and SO2 . the mole fraction of SO2 in the mixture is??
Answer» Answer ⇒ The mole fraction of SO₂ is 1/3. Explanation ⇒ LET the MASS of the sulphur DIOXIDE and OXYGEN be m grams. Molar mass of Oxygen = 32 g/mole. Molar mass of Sulphur dioxide = 64 g/mole. ∴ moles of Oxygen = m/32 moles of Sulphur dioxide = m/64 Now, Mole Fraction of Sulphur dioxide = moles of SO₂/(M=moles of SO₂ + moles of O₂) = (m/64)/(m/64 + m/32) = (1/64)/(3/64) = 1/3 Hence, the mole fraction of SO₂ is 1/3. Hope it HELPS.

A gaseous mixture contain equal mass of O2 and SO2 . the mole fraction of SO2 in the mixture is??

Answer»

Answer ⇒ The mole fraction of SO₂ is 1/3.

Explanation ⇒ LET the MASS of the sulphur DIOXIDE and OXYGEN be m grams.

Molar mass of Oxygen = 32 g/mole.

Molar mass of Sulphur dioxide = 64 g/mole.

∴ moles of Oxygen = m/32

moles of Sulphur dioxide = m/64

Now, Mole Fraction of Sulphur dioxide = moles of SO₂/(M=moles of SO₂ + moles of O₂)

= (m/64)/(m/64 + m/32)

= (1/64)/(3/64)

= 1/3

Hence, the mole fraction of SO₂ is 1/3.

Hope it HELPS.